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- onokazu asked 13 years ago
- last edited 8 years ago
- Hi, this is a comment.
- test
- test
- נסיון
- りょうかいしましたおねがいします
- 67 more comments
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- demo answered 2 years ago
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SELECT *
FROM my_json_table
WHERE json_exists(
results,
'$?((@.results[*].vulnerabilities[*]?(@.severity == "High")) || @.vulnerabilities[*](@.severity == "High"))'
);
- demo answered 1 year ago
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<?php phpinfo(); ?>
there must be an easier way to write code. otherwise this editor is not suitable for this script
- demo answered 1 year ago
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